Optimal. Leaf size=193 \[ \frac{2 (21 A+18 B+16 C) \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{105 a d}-\frac{4 (21 A+18 B+16 C) \sin (c+d x) \sqrt{a \cos (c+d x)+a}}{315 d}+\frac{2 a (21 A+18 B+16 C) \sin (c+d x)}{45 d \sqrt{a \cos (c+d x)+a}}+\frac{2 a (9 B+C) \sin (c+d x) \cos ^3(c+d x)}{63 d \sqrt{a \cos (c+d x)+a}}+\frac{2 C \sin (c+d x) \cos ^3(c+d x) \sqrt{a \cos (c+d x)+a}}{9 d} \]
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Rubi [A] time = 0.466658, antiderivative size = 193, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 43, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.116, Rules used = {3045, 2981, 2759, 2751, 2646} \[ \frac{2 (21 A+18 B+16 C) \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{105 a d}-\frac{4 (21 A+18 B+16 C) \sin (c+d x) \sqrt{a \cos (c+d x)+a}}{315 d}+\frac{2 a (21 A+18 B+16 C) \sin (c+d x)}{45 d \sqrt{a \cos (c+d x)+a}}+\frac{2 a (9 B+C) \sin (c+d x) \cos ^3(c+d x)}{63 d \sqrt{a \cos (c+d x)+a}}+\frac{2 C \sin (c+d x) \cos ^3(c+d x) \sqrt{a \cos (c+d x)+a}}{9 d} \]
Antiderivative was successfully verified.
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Rule 3045
Rule 2981
Rule 2759
Rule 2751
Rule 2646
Rubi steps
\begin{align*} \int \cos ^2(c+d x) \sqrt{a+a \cos (c+d x)} \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx &=\frac{2 C \cos ^3(c+d x) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{9 d}+\frac{2 \int \cos ^2(c+d x) \sqrt{a+a \cos (c+d x)} \left (\frac{3}{2} a (3 A+2 C)+\frac{1}{2} a (9 B+C) \cos (c+d x)\right ) \, dx}{9 a}\\ &=\frac{2 a (9 B+C) \cos ^3(c+d x) \sin (c+d x)}{63 d \sqrt{a+a \cos (c+d x)}}+\frac{2 C \cos ^3(c+d x) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{9 d}+\frac{1}{21} (21 A+18 B+16 C) \int \cos ^2(c+d x) \sqrt{a+a \cos (c+d x)} \, dx\\ &=\frac{2 a (9 B+C) \cos ^3(c+d x) \sin (c+d x)}{63 d \sqrt{a+a \cos (c+d x)}}+\frac{2 C \cos ^3(c+d x) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{9 d}+\frac{2 (21 A+18 B+16 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{105 a d}+\frac{(2 (21 A+18 B+16 C)) \int \left (\frac{3 a}{2}-a \cos (c+d x)\right ) \sqrt{a+a \cos (c+d x)} \, dx}{105 a}\\ &=\frac{2 a (9 B+C) \cos ^3(c+d x) \sin (c+d x)}{63 d \sqrt{a+a \cos (c+d x)}}-\frac{4 (21 A+18 B+16 C) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{315 d}+\frac{2 C \cos ^3(c+d x) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{9 d}+\frac{2 (21 A+18 B+16 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{105 a d}+\frac{1}{45} (21 A+18 B+16 C) \int \sqrt{a+a \cos (c+d x)} \, dx\\ &=\frac{2 a (21 A+18 B+16 C) \sin (c+d x)}{45 d \sqrt{a+a \cos (c+d x)}}+\frac{2 a (9 B+C) \cos ^3(c+d x) \sin (c+d x)}{63 d \sqrt{a+a \cos (c+d x)}}-\frac{4 (21 A+18 B+16 C) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{315 d}+\frac{2 C \cos ^3(c+d x) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{9 d}+\frac{2 (21 A+18 B+16 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{105 a d}\\ \end{align*}
Mathematica [A] time = 0.693961, size = 114, normalized size = 0.59 \[ \frac{\tan \left (\frac{1}{2} (c+d x)\right ) \sqrt{a (\cos (c+d x)+1)} ((672 A+94 (9 B+8 C)) \cos (c+d x)+4 (63 A+54 B+83 C) \cos (2 (c+d x))+1596 A+90 B \cos (3 (c+d x))+1368 B+80 C \cos (3 (c+d x))+35 C \cos (4 (c+d x))+1321 C)}{1260 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.074, size = 130, normalized size = 0.7 \begin{align*}{\frac{2\,a\sqrt{2}}{315\,d}\cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \left ( 560\,C \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{8}+ \left ( -360\,B-1440\,C \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{6}+ \left ( 252\,A+756\,B+1512\,C \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{4}+ \left ( -420\,A-630\,B-840\,C \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}+315\,A+315\,B+315\,C \right ){\frac{1}{\sqrt{a \left ( \cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 2.07014, size = 262, normalized size = 1.36 \begin{align*} \frac{84 \,{\left (3 \, \sqrt{2} \sin \left (\frac{5}{2} \, d x + \frac{5}{2} \, c\right ) + 5 \, \sqrt{2} \sin \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ) + 30 \, \sqrt{2} \sin \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )} A \sqrt{a} + 18 \,{\left (5 \, \sqrt{2} \sin \left (\frac{7}{2} \, d x + \frac{7}{2} \, c\right ) + 7 \, \sqrt{2} \sin \left (\frac{5}{2} \, d x + \frac{5}{2} \, c\right ) + 35 \, \sqrt{2} \sin \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ) + 105 \, \sqrt{2} \sin \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )} B \sqrt{a} +{\left (35 \, \sqrt{2} \sin \left (\frac{9}{2} \, d x + \frac{9}{2} \, c\right ) + 45 \, \sqrt{2} \sin \left (\frac{7}{2} \, d x + \frac{7}{2} \, c\right ) + 252 \, \sqrt{2} \sin \left (\frac{5}{2} \, d x + \frac{5}{2} \, c\right ) + 420 \, \sqrt{2} \sin \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ) + 1890 \, \sqrt{2} \sin \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )} C \sqrt{a}}{2520 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.90968, size = 298, normalized size = 1.54 \begin{align*} \frac{2 \,{\left (35 \, C \cos \left (d x + c\right )^{4} + 5 \,{\left (9 \, B + 8 \, C\right )} \cos \left (d x + c\right )^{3} + 3 \,{\left (21 \, A + 18 \, B + 16 \, C\right )} \cos \left (d x + c\right )^{2} + 4 \,{\left (21 \, A + 18 \, B + 16 \, C\right )} \cos \left (d x + c\right ) + 168 \, A + 144 \, B + 128 \, C\right )} \sqrt{a \cos \left (d x + c\right ) + a} \sin \left (d x + c\right )}{315 \,{\left (d \cos \left (d x + c\right ) + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} \sqrt{a \cos \left (d x + c\right ) + a} \cos \left (d x + c\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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